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2x^2+3x^2=31.25
We move all terms to the left:
2x^2+3x^2-(31.25)=0
We add all the numbers together, and all the variables
5x^2-31.25=0
a = 5; b = 0; c = -31.25;
Δ = b2-4ac
Δ = 02-4·5·(-31.25)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-25}{2*5}=\frac{-25}{10} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+25}{2*5}=\frac{25}{10} =2+1/2 $
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